invalid_pattern_variable_in_shared_case_scope

The variable '{0}' doesn't have the same type and/or finality in all cases that share this body.

The variable '{0}' is available in some, but not all cases that share this body.

The variable '{0}' is not available because there is a label or 'default' case.

The analyzer produces this diagnostic when multiple case clauses in a switch statement share a body, and at least one of them declares a variable that is referenced in the shared statements, but the variable is either not declared in all of the case clauses or it is declared in inconsistent ways.

If the variable isn't declared in all of the case clauses, then it won't have a value if one of the clauses that doesn't declare the variable is the one that matches and executes the body. This includes the situation where one of the case clauses is the default clause.

If the variable is declared in inconsistent ways, either being final in some cases and not final in others or having a different type in different cases, then the semantics of what the type or finality of the variable should be are not defined.

The following code produces this diagnostic because the variable a is only declared in one of the case clauses, and won't have a value if the second clause is the one that matched x:

void f(Object? x) {
  switch (x) {
    case int a when a > 0:
    case 0:
      a;
  }
}

The following code produces this diagnostic because the variable a isn't declared in the default clause, and won't have a value if the body is executed because none of the other clauses matched x:

void f(Object? x) {
  switch (x) {
    case int a when a > 0:
    default:
      a;
  }
}

The following code produces this diagnostic because the variable a won't have a value if the body is executed because a different group of cases caused control to continue at the label:

void f(Object? x) {
  switch (x) {
    someLabel:
    case int a when a > 0:
      a;
    case int b when b < 0:
      continue someLabel;
  }
}

The following code produces this diagnostic because the variable a, while being assigned in all of the case clauses, doesn't have then same type associated with it in every clause:

void f(Object? x) {
  switch (x) {
    case int a when a < 0:
    case num a when a > 0:
      a;
  }
}

The following code produces this diagnostic because the variable a is final in the first case clause and isn't final in the second case clause:

void f(Object? x) {
  switch (x) {
    case final int a when a < 0:
    case int a when a > 0:
      a;
  }
}

If the variable isn't declared in all of the cases, and you need to reference it in the statements, then declare it in the other cases:

void f(Object? x) {
  switch (x) {
    case int a when a > 0:
    case int a when a == 0:
      a;
  }
}

If the variable isn't declared in all of the cases, and you don't need to reference it in the statements, then remove the references to it and remove the declarations from the other cases:

void f(int x) {
  switch (x) {
    case > 0:
    case 0:
  }
}

If the type of the variable is different, decide the type the variable should have and make the cases consistent:

void f(Object? x) {
  switch (x) {
    case num a when a < 0:
    case num a when a > 0:
      a;
  }
}

If the finality of the variable is different, decide whether it should be final or not final and make the cases consistent:

void f(Object? x) {
  switch (x) {
    case final int a when a < 0:
    case final int a when a > 0:
      a;
  }
}